Das mußte jetzt einfach mal gesagt werden!
... und ja, ich kenne genug Wege, wie ich das trotzdem sehen kann ... was das Ganze noch absurder macht und zeigt, dass sie einfach keinen Plan haben (und es wohl auch nicht mehr lernen werden).
★ Einmal mit Profis! ★
Salatbett aus: Eichblattsalat, Romanosalat, Salatgurke, rote Paprika, gedünstete Zwiebelstreifen, halbierte Cherrytomaten, gewürfelter Fetakäse.
Darüber Vinaigrette: 10 cl Olivenöl, 2 cl weißer Balsamico, 2 Knoblauchzehen, 1 TL Senf, Salz, Pfeffer zusammen in den Mixer geben.
Darauf gebratene Austernpilze und Entenbrust legen.
Dazu Knoblauchbaguette und Rotwein reichen.
Guten Appetit!
... get on my nerves for quite some time.
As far as I could find out they are used by Google Analytics and represent "The five dimensions of campaign tracking" (Source, Medium, Term, Content, Campaign).
As I have written in prior posts, I am not too fond of being tracked, so I wrote this little python snippet, to delete these information from URLs. I use it in a few of my gateway programs and it can be used eg. in an URL filter for the squid proxy (see redirect_program directive).
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import re
UTM_TAGS = (
u'utm_source',
u'utm_medium',
u'utm_term',
u'utm_content',
u'utm_campaign'
)
utm_re = list()
for ut in UTM_TAGS:
# unescaped form: &utm_name=value
utm_re.append(re.compile(u"([?&]"+ut+u"=[^&]*)"))
# escaped form: &utm_name=value
utm_re.append(re.compile(u"(&"+ut+u"=[^&]*)"))
def unUTM(url):
# check if the URL is parameterized
if 0 <= url.find("?"):
# double the parameter delimiter, so we won't lose it
url = url.replace("?", "??")
for p in utm_re:
url = p.sub(u"", url)
# clean up leftover mess
url = url.replace("??","?").replace("?&", "?").strip("?")
return(url)
Trying to incorporate BlackJack's comments led me to the following code:
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import re
UTM_TAGS = (
u'utm_source',
u'utm_medium',
u'utm_term',
u'utm_content',
u'utm_campaign'
)
utm_re = re.compile(u''.join((
u'(^|&(amp;)?)(', # either at start or preceeded by '&' or '&'
u'|'.join(UTM_TAGS), # all tags as alternatives
u'=)[^&]*' # followed by '=' and all chars upto next '&'
)))
def unUTM(url):
# check if the URL is parameterized
if '?' in url:
(url, params) = url.split('?', 1)
params = utm_re.sub(u'', params)
if '' != params:
params = re.compile(u'^&(amp;)?').sub(u'', params)
url = u'?'.join((url, params))
return(url)
Armin 'argv[0]' Gruner has probably the most elegant solution that doesn't even use regex:
#!/usr/bin/env python
# -*- coding: utf-8 -*-
from urlparse import parse_qs, urlsplit, urlunsplit
from urllib import urlencode
from cgi import escape
def unUTM(url):
res = urlsplit(url)
if not res.query:
return url
qdict = parse_qs(res.query)
map(lambda key: qdict.pop(key), filter(lambda key: key.startswith('utm_'), qdict.keys()))
res = list(res))
res[3] = escape(urlencode(qdict, doseq=1))
return urlunsplit(res)